Mr. Voeller's Chemistry Class
Wednesday, December 16, 2015
Tuesday, December 15, 2015
Friday, October 23, 2015
Sunday, October 18, 2015
Next writing assignment
Earth is fortunate to fall in the "Goldilocks Zone" and be at just about the right temperature for life to exist. However another major factor that supports life on our planet is our atmosphere. Describe three reasons that EACH of our neighboring planets could not support life at their surfaces. Use the following article in your response: Chem Matters Article
Thursday, September 24, 2015
Sunday, January 4, 2015
Last Weekly Assignment! (due Thursday)
Before you start the homework I will remind you that the prefix "kilo-" means 1000, resulting in the conversions: 1 kJ = 1000 J
and 1 kcal = 1000 cal
A kilocalorie is the type of calorie that we are used to when we look at nutritional information, and because it is so common scientists have decided to denote it with a "capital" c as follows: Cal
So any time you see Cal or Calorie, think kcal !!!
Do the following problems from the worksheets handed out in class:
#35,37,38,40,41,46,47,52,54,71,72
(Without some searching on your own, problems 37, 38, and 71 will not be possible for you to do until after Wednesday's lecture.)
and 1 kcal = 1000 cal
A kilocalorie is the type of calorie that we are used to when we look at nutritional information, and because it is so common scientists have decided to denote it with a "capital" c as follows: Cal
So any time you see Cal or Calorie, think kcal !!!
Do the following problems from the worksheets handed out in class:
#35,37,38,40,41,46,47,52,54,71,72
(Without some searching on your own, problems 37, 38, and 71 will not be possible for you to do until after Wednesday's lecture.)
Sunday, December 21, 2014
#14 and #15 on the homework due 12/19
14.
2 H3PO4 + 3 Ca(OH)2 à Ca3(PO4)2 +
6 H2O
0.75 L x (6 mol/L) = 4.5 mol H3PO4
4.5 mol H3PO4 ∙ (6 mol H2O/2
mol H3PO4) ∙ (18.0128 g H2O/ 1 mol H2O)
= 243 g water
4.5 mol H3PO4 ∙ (1 mol Ca3(PO4)2/2
mol H3PO4) ∙ (310 g Ca3(PO4)2/1
mol Ca3(PO4)2) = 698 g calcium phosphate
15.
3 H2SO4 + 2 Al(OH)3 à Al2(SO4)3 +
6 H2O
0.250 L ∙ (2.5 mol Al(OH)3 / 1 L) = 0.625 mol Al(OH)3
0.625 mol Al(OH)3 ∙ (3 mol H2SO4/2
mol Al(OH)3) = 0.9375 mol H2SO4
18.0 = 0.9375/x
X = 0.0521 L = 52.1 mL H2SO4
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